2004-10-20
Rounding a floating point value to a certain precision
For my work, I needed to round a floating point value (double in C#) to a precision of 0.05. Unfortunately, Math.Round only lets you round a value to the nearest decimal. That means you can only round to 0.1, 0.01, 0.001, ... To round your values to 0.05, or 0.25, or whatever, I created the following function:
In C#:
In C#:
public static double Round(double x, int numerator, int denominator) { // returns the number nearest x, with a precision of numerator/denominator // example: Round(12.1436, 5, 100) will round x to 12.15 (precision = 5/100 = 0.05) long y = (long)Math.Floor(x * denominator + (double)numerator / 2.0); return (double)(y - y % numerator)/(double)denominator; }In Euphoria:
global function Round(atom x, integer numerator, integer denominator) -- returns the number nearest x, with a precision of numerator/denominator -- example: Round(12.1436, 5, 100) will round x to 12.15 (precision = 5/100 = 0.05) integer y y = floor(x * denominator + numerator / 2.0) return (y - remainder(y, numerator)) / denominator end function